I saw some equation in a log recently and I believe it went something as follows:
$v_1$ : flying North, $\ \ v_2$ : flying West, $\ \ v_3$ : flying South.
$$ \text{TAS} = \frac 1 2 \sqrt{v_1^2+v_2^2+v_3^2+\frac{v_2^2}{v_1^2+v_3^2}} = 199.7 $$
Which seems a little high for an RV-4 with O-320, even at 8,000ft and max power.
I may be mixing up the subscripts on the $\frac{v_2^2}{v_1^2+v_3^2}$ part, but those are the only subscripts that make sense by symmetry.
How does this airspeed calculation work?
I can imagine flying in a square and then taking the average $\frac 1 4 \left( v_N + v_W + v_S + v_E \right)$ (GPS-calculated groundspeeds) and I see the problem with that is that while the headwind and tailwind components cancel, the crosswind will not. How does taking the euclidean distance between velocities fix this and what is the final term $\frac{v_2^2}{v_1^2+v_3^2}$?
I just found a paper on this that seems to correspond to the TAS measurement technique this test pilot was using: I believe it is David Rogers Horseshoe Heading technique.
But I don't see how the equation presented above relates to any on that paper.
So what is the equation above?
For context, the reason we would not want to use the normal equation based on CAS, is because when flight testing a new aircraft we do not know for sure what the IAS→CAS conversion is, so it is necessary to determine it (or verify it, if building a kit). One way of doing that is to determine TAS independently (here using GPS and DR's HHT) and then calculate CAS from the TAS so that you can create your IAS→CAS correction table.