I have a Mexican DGAC licence. Can I work in other countries, or do I need to get another licence? (for example an FAA one if I want to work in the US)
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2$\begingroup$ Which country's DGAC do you mean (there are several)? We have a lot of questions about using a license from one country in another one, this one might be relevant for you. $\endgroup$– PondlifeCommented Nov 14, 2017 at 2:14
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$\begingroup$ Mexico. I guess you get it the same way as if you had a EASA Licence so thanks! $\endgroup$– IanCommented Nov 14, 2017 at 3:19
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$\begingroup$ In the US you can do certain commercial flying, such as glider towing, with an FAA license, but I don't believe you could with your Mexican license. $\endgroup$– J WCommented Nov 14, 2017 at 17:55
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No. If you want to make commercial activities, you need a commercial license.
I remind you the definition of commercial flight
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1$\begingroup$ This is not strictly true under FAA regulations. In the US, with an FAA private pilot certificate, certain commercial flying is authorized, for example glider towing. $\endgroup$– J WCommented Nov 14, 2017 at 17:40
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$\begingroup$ @JWalters Glider towing is not defined as commercial flight! $\endgroup$ Commented Nov 16, 2017 at 9:10
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1$\begingroup$ The question you linked to isn't really relevant here: it's about how the CBP defines commercial flight, not how the FAA defines it. $\endgroup$– PondlifeCommented Nov 16, 2017 at 14:29
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$\begingroup$ @Pondlife it is an ICAO definition. It is the same worldwide. $\endgroup$ Commented Nov 17, 2017 at 9:07
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1$\begingroup$ See Martindell (2009) and MacKenzie (2009). The FAA defines commercial flying, in pertinent part, as: "any nonmilitary flying as a required crewmember [...] for which the crewmember is paid for his or her services." See also 14 CFR 61.113(g):
A private pilot [...] may act as a pilot in command of an aircraft towing a glider or unpowered ultralight vehicle.
See also Umphres (2010): "§61.113(g) permits a private pilot to act as PIC for compensation or hire of an aircraft towing a glider". $\endgroup$– J WCommented Nov 21, 2017 at 11:20