Acceleration from a standing start is based on Force and Mass until the object gains enough velocity for drag to become a considerable factor.
One must consider the increase in drag as well as the mass accelerating from Mach 0.6 to 0.8. There is also the Mach effect with additional drag at high subsonic speeds.
The Raptors twin Pratt&Whitney F119 engines produce 2 x 26,000 lbs of thrust each dry and 2 x 35,000 lbs of thrust in afterburner. The afterburners add an additional 18,000 lbs of thrust force. For 60,000 lb weight, afterburners accelerate the aircraft:
18000 lbf × 4.45 N/lbf = 80068 N = 80068 kg m/s$^2$
80068 N = 27000 kg x acceleration
acceleration from afterburners = 3.0 m/s$^2$
If you had some idea of the thrust required to go Mach 0.6 and Mach 0.8 at a constant speed, then you subtract the drag penalty from the known thrust value with afterburner. The excess thrust is available for acceleration.
The main parameters for optimal performance are minimum weight, minimum drag and maximum thrust.
From a standing start, the motorcycle (and the cheetah) will be ahead of the F-22, but not for long.
The F-22's 70,000 pounds of thrust will continue to accelerate its 60,000 lbs of mass as the cheetah, then the motorcycle reach their top speeds.
But off the line, the cheetah and motorcycle acceleration is greater than that of the F-22. It should be noted that the best acceleration for the jet will also be at lower speeds, where there is less drag, but will never approach that of a cheetah's best.
Fast twitch muscle acceleration rates come from boxer data:
Here a 25 mph throw (11 meters/second) covers a distance of around 0.7 meter. The average velocity is 5.5 m/s. The distance is covered in: 1 s/5.5m × 0.7m = 0.13 seconds
The initial acceleration is 11m/0.13s$^2$ = 85 m/s$^2$
Top speed of 30 m/s in around 1.5 seconds yielding an acceleration of 20 m/s$^2$ (cheetah has least mass but also lowest thrust. Drag factors rapidly slow acceleration).
Time to cover 100 m:
d acc = 1/2 × 30 m/1.5 s$^2$ x 1.5$^2$ = 22.5 m
d rem = 100 m - 22.5 m = 77.5 m
t rem = 77.5 m / 30 m/s = 2.6 s
Total cheetah time 100m = 1.5 s + 2.6 s = 4.1 s (hungry)
The motorcycle is 14 m/s$^2$ 0 to 30 m/s in around 2 seconds
Top speed around 60 m/s
d acc = 1/2 × 14 m/s$^2$ × 2$^2$ = 28 m
d rem = 100 m - 28 m = 72 m
The motorcycle (using gears) continues to accelerate by (estimated) 5 m/s$^2$, covering 30.5 m in second 3, and 35.5 m in second 4
After 4 seconds it's distance traveled is:
d trav = 28 m + 30.5 m + 35.5 m = 94 m
After 4.1 seconds:
94 m + (38 m/s × 0.1 sec) = 97.8 m (very close!)
Special note to Hyabusa fans:
400 m (1/4 mile) ≈ 1/2 × a × 10 s$^2$
Acceleration = 8 m/s$^2$
This racing motorbike can develop 180+ horsepower by revving to very high rpm before going through its gears. It's observed acceleration is remarkably constant. Estimated time to 100 m:
100m = 1/2 × 8 m/s$^2$ × t$^2$
t = around 5 seconds (we're in the ballpark!)
The F-22 acceleration rate from a standing start with afterburners
70000 lbf × 4.45 N/lbf = 311500 N
311500 N / 27000 kg = 11.5 m/s$^2$
Because drag only marginally affects its acceleration at lower speeds and huge N thrust, it is constantly accelerating at 11.5 m/s$^2$. After 4.1 seconds:
d trav = 1/2 × 11.5 m/s$^2$ x 4.1$^2$ = 97 m !
From this we can see the cheetah and motorcycle acceleration will be greater than the F-22 initially, with the rapidly decreasing acceleration of the ground competitors after a few seconds making an actual 100 meter race a very entertaining match up. The Navy figured all this out years ago, which is why they have catapults on their aircraft carriers!