Rocket produce constant thrust with speed,that mean increase power with speed.
If you limit "power" to mean the change in energy over time of the vehicle + unburned fuel, then yes, that's correct.
Where this increase in power come from if fuel burn rate is constant,how explain this in reference frame of rocket without violate physics laws?
It comes from only looking at part of what the engine is doing. The other change the engine makes is a change in energy of the fuel/exhaust.
At the first instant that the engine is running (when the rocket is still stationary), 100% of the combustive power of the engine goes into accelerating the fuel into exhaust. The power going into the vehicle is zero, but the engine is still doing something.
As the rocket accelerates in that frame, we see the ratio of where the power goes changes. More power goes into accelerating the vehicle and less power goes into accelerating the exhaust.
If we assume the engine is running with nearly constant fuel flow, then we would see at any instant
$$\Delta E_{\text{combustion}} = \Delta E_{\text{rocket}} + \Delta E_{\text{fuel}}$$
As it accelerates away, the amount going into the rocket term is increasing while the amount going into the fuel term is decreasing. (And in fact that final term can become negative so that the energy going to the rocket is greater than the energy from combustion).
Does turbo fan and turbo jet also produce constant thrust with speed?
That's a useful approximation over a large range of operating conditions. But unlike a rocket, airplanes have increasing drag forces as they accelerate. This limits the top speed and the acceleration possible. Since most airplanes fly with a cruise (non-accelerating) portion dominating, the idea of how the KE of the airframe changes over time is much less interesting.