Rewatched the MythBusters episode to get their speeds and data. Now, it's time to do some math.

$m = \frac{4lb}{32.174ft/s^2} = 0.124slug$

$V = 140 mi/h = 205.3ft/s$

$t = 0.007s$

In both cases, $a = V1/t = 29333 ft/s^2$

Since $F_{ave} = ma$, $F_{ave} = 0.124slug*29333ft/s^2 = 3647lb$

Separately, if we consider the numbers in the wikipedia article you posted, $V = 350 mi/h = 513 ft/s$. If we assume the same rate of energy dissipation as the MythBusters test and a 4lb chicken, then:

$k_{MB} = \frac{1}{2}mv^2 = \frac{1}{2}(0.124slug)(205.3ft/s)^2 = 2613ft-lb$

$k_{MB}/t_{MB} = 2613ft-lb/0.007s = 373,311 ft-lb/s$

$k_{wiki} = \frac{1}{2}(0.124slug)(513ft/s)^2 = 16316ft-lb$

$t_{wiki} = \frac{k_{wiki}}{\frac{k_{MB}}{t_{MB}}} = \frac{16316ft-lb}{373311ft-lb/s} = 0.043s$

Then, $a = V/t = \frac{513ft/s}{0.043s} = 11737ft/s^2$

and $F = ma = 0.124slug*11737ft/s^2 = 1455lb$

If instead we assume the deceleration time is constant:

$a_{wiki} = \frac{513ft/s}{0.007s} = 73285ft/s^2$

$F_{wiki} = 0.124slug*73285ft/s^2 = 9087lb$

And interestingly enough, based on the MythBusters' testing, a frozen and thawed chicken would impart the same force.

Rewatched the MythBusters episode to get their speeds and data. Now, it's time to do some math.

$m = \frac{4~\mathrm{lb}}{32.174~\mathrm{ft/s}^2} = 0.124~\mathrm{slug}$

$V = 140~\frac{\mathrm{mi}}{\mathrm{h}} = 205.3~\frac{\mathrm{ft}}{\mathrm{s}}$

$t = 0.007~\mathrm{s}$

In both cases, $a = V1/t = 29333~\mathrm{ft/s}^2$

Since $F_\mathrm{avg} = ma$, $F_\mathrm{avg} = 0.124~\mathrm{slug} \cdot 29333~\mathrm{ft/s}^2 = 3647~\mathrm{lb}$

Separately, if we consider the numbers in the wikipedia article you posted, $V = 350~\mathrm{mi/h} = 513~\mathrm{ft/s}$. If we assume the same rate of energy dissipation as the MythBusters test and a 4lb chicken, then:

$k_\mathrm{MB} = \frac{1}{2}mv^2 = \frac{1}{2}(0.124~\mathrm{slug}) \cdot (205.3~\mathrm{ft/s})^2 = 2613~\mathrm{ft}\cdot\mathrm{lb}$

$\frac{k_\mathrm{MB}}{t_\mathrm{MB}} = \frac{2613~\mathrm{ft}\cdot\mathrm{lb}}{0.007~\mathrm{s}} = 373,311~\mathrm{ft}\cdot\mathrm{lb/s}$

$k_\mathrm{wiki} = \frac{1}{2}(0.124~\mathrm{slug})(513~\mathrm{ft/s})^2 = 16316~\mathrm{ft}\cdot\mathrm{lb}$

$t_\mathrm{wiki} = \frac{k_\mathrm{wiki}}{\frac{k_\mathrm{MB}}{t_\mathrm{MB}}} = \frac{16316~\mathrm{ft}\cdot\mathrm{lb}}{373311~\mathrm{ft}\cdot\mathrm{lb/s}} = 0.043~\mathrm{s}$

Then, $a = V/t = \frac{513~\mathrm{ft/s}}{0.043~\mathrm{s}} = 11737~\mathrm{ft/s}^2$

and $F = ma = 0.124~\mathrm{slug} \cdot 11737~\mathrm{ft/s}^2 = 1455~\mathrm{lb}$

If instead we assume the deceleration time is constant:

$a_\mathrm{wiki} = \frac{513~\mathrm{ft/s}}{0.007~\mathrm{s}} = 73285~\mathrm{ft/s}^2$

$F_\mathrm{wiki} = 0.124~\mathrm{slug} \cdot 73285~\mathrm{ft/s}^2 = 9087~\mathrm{lb}$

And interestingly enough, based on the MythBusters' testing, a frozen and thawed chicken would impart the same force.