The math to verify Mr. Philip Johnson is given below. The maximum bank angle for a normal category aircraft is 60deg at 2G's. The formula for turn radius is
V^2
R = ----------
G*tan(bank)
given
V=168900(ft/sec) = 1000kt * 1.68
G=32.2(ft/sec)
tan(bank) = 1.7(60deg)
R=(1690^2) / (32.2 * 1.7) = 52175(ft) = 9.8mi
$R = \frac{V^2}{G\cdot tan(bank)}$
19.76.4mi given
$V = 168900(ft/sec) = 1000kt \cdot 1.68$
$G = 32.2(ft/sec)$
$tan(bank) = 1.7(60deg) $
$R = (1690^2) / (32.2 * 1.7) = 52175(ft) = 9.8mi$
$19.76.4mi$ diameter = 9.8(radius) x 2$9.8(radius) \cdot 2$