Timeline for What are the factors required to estimate the minimum required power for an experimental aircraft of a specific mass?
Current License: CC BY-SA 3.0
14 events
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| Nov 4, 2017 at 6:21 | vote | accept | CommunityBot | moved from User.Id=18035 by developer User.Id=7937 | |
| Nov 4, 2017 at 6:20 | comment | added | user18035 | That is a fabulous answer - thanks a ton! @Koyovis - Your answer was awesome too! I shall choose Peter Kampf's answer for the sake of completeness, but both the answers were very useful (I'm yet to understand the equations fully though). | |
| Nov 4, 2017 at 5:58 | comment | added | Peter Kämpf | @AnandS: The Diamond only cruises at 90 kt, not 100. This is a major difference. Altitude makes little difference - what you gain in lower drag, you lose in power with a normally aspirated engine as density drops. At high speed the larger weight does not hurt much, but a bigger wing does. Conversely, a bigger wing allows you to fly slower, so the minimum power goes down. But so does the speed regime you can fly in. | |
| Nov 4, 2017 at 5:18 | comment | added | user18035 | How does the much heavier Super Diamond Mk 1 fly at 90 kts with a 60 hp engine? Is it due to its low ceiling of 8000 ft? Will increasing my wing area reduce my minimum required power? | |
| Nov 4, 2017 at 0:53 | comment | added | Koyovis | This is a great way to keep us busy :) | |
| Nov 3, 2017 at 23:31 | history | edited | Peter Kämpf | CC BY-SA 3.0 |
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| Nov 3, 2017 at 23:22 | comment | added | Peter Kämpf | @Koyovis: Now I have to admit an error, too. Somehow my dynamic pressure included the wing area. Also, I have added a margin between continuous and installed power, so my engine needs to be rated at 70 hp. | |
| Nov 3, 2017 at 23:20 | history | edited | Peter Kämpf | CC BY-SA 3.0 |
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| Nov 3, 2017 at 23:06 | history | edited | Peter Kämpf | CC BY-SA 3.0 |
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| Nov 3, 2017 at 22:41 | comment | added | Peter Kämpf | @AnandS: All is calculated at sea level, but I will add FL 100 math as well. | |
| Nov 3, 2017 at 16:56 | comment | added | user18035 | In which equation have you given the cruise altitude / air density as an input? How do I calculate the minimum required power for a max. cruise altitude of 10000 ft. and what is the cruise altitude you have used as a parameter? | |
| Nov 3, 2017 at 16:07 | comment | added | Peter Kämpf | @Koyovis: Yes, that's better, only your minimum drag speed lift coefficient is actually that for minimum power. | |
| Nov 3, 2017 at 15:45 | comment | added | Koyovis | Um - I made an error, which is corrected. Get 56 hp now! | |
| Nov 3, 2017 at 7:30 | history | answered | Peter Kämpf | CC BY-SA 3.0 |