Timeline for Why can't you ditch your aircraft in the sea?
Current License: CC BY-SA 3.0
23 events
when toggle format | what | by | license | comment | |
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Jul 19, 2018 at 1:13 | vote | accept | user541686 | ||
S Jan 2, 2018 at 17:17 | history | suggested | Jeff B | CC BY-SA 3.0 |
Fix missing word
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Jan 2, 2018 at 16:59 | review | Suggested edits | |||
S Jan 2, 2018 at 17:17 | |||||
S Jan 2, 2018 at 14:44 | history | rollback | GdD |
Rollback to Revision 4 - Edit approval overridden by post owner or moderator
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Jan 1, 2018 at 6:35 | history | suggested | Jeff B | CC BY-SA 3.0 |
Fix missing word problem and shorten some run-on sentences, etc.
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Jan 1, 2018 at 0:36 | review | Suggested edits | |||
S Jan 2, 2018 at 14:44 | |||||
Oct 17, 2017 at 9:14 | comment | added | Giacomo Catenazzi | Additionally: it is very difficult to know where is the ocean. You have no references on the relative height. You cannot predict if you see large waves at heights, or just small waves and you are very near the water. This make more difficult to plan a good stall just above the water. Hudson river landing had not such problem, they had a bridge and coast (buildings, cars) to evaluate distances. | |
Oct 16, 2017 at 19:22 | comment | added | Michael Seifert | Note that that later in the story, a Coast Guard flying boat flies over him but cannot land because "the seas were high". So ditching into those conditions wouldn't be the best idea. | |
Oct 16, 2017 at 12:50 | comment | added | Todd Wilcox | Regardless of how wings create lift, we know that stalling is a factor, which is why it's not possible to bleed off all of one's airspeed and maintain control. We could know nothing about the physics of the situation and still be faced with that certain reality. | |
Oct 16, 2017 at 12:44 | history | edited | GdD | CC BY-SA 3.0 |
restructured for clarity.
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Oct 16, 2017 at 11:58 | comment | added | GdD | That decade in university paid off @MichaelKjörling :) | |
Oct 16, 2017 at 11:57 | comment | added | user | @GdD Yay, something sticks from my studying aerodynamics! :-) | |
Oct 16, 2017 at 11:56 | comment | added | GdD | @MichaelKjörling, you are entirely right, I did over-simplify the explanation of lift as going into it in detail wasn't really key to my answer. | |
Oct 16, 2017 at 11:52 | history | edited | GdD | CC BY-SA 3.0 |
responded to more comments.
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Oct 16, 2017 at 11:43 | comment | added | GdD | @Stanislasdrg, sure, if the sea is calm you could use ground effect to reduce your speed some, maybe 10% as a guess, not much overall. If the sea is rough you could be flying into and out of ground effect, which is dangerous if you get too slow, probably one of the reasons most ditching procedures specify to ditch at landing speed. | |
Oct 16, 2017 at 11:37 | comment | added | user541686 | @MichaelKjörling: Hmm, okay, thanks. +1 | |
Oct 16, 2017 at 11:16 | comment | added | user | @Mehrdad I'm not up to actually explaining the details, but GdD's explanation is correct, to within the limits of what I think GdD even attempted to explain - there are whole books on aerodynamics which devote a significant portion to just how a wing actually creates lift. Air above the wing (where "above" and "below" are problematic terms in their own right!) isn't moving faster - doing so would require impartment of energy toward the aircraft rear on the air by the wing (from where?). The air is however at a lower pressure above than below the wing, which contributes to creating lift. | |
Oct 16, 2017 at 11:07 | comment | added | user541686 | @GdD: Thanks for the update! Now what I'm wondering about is, is what you're saying about aerodynamics actually correct? Specifically, the part where you say "A wing flies because the shape of it creates a pocket of low pressure above it, which requires smooth airflow" seems to be based on the classical (incorrect?) explanation of how wings work. From my understanding, most of the lift of a wing comes from simply a redirection of the horizontal force to vertical (due to collision with the wing). Perhaps I'm wrong though? See here. | |
Oct 16, 2017 at 10:59 | comment | added | Standaa - Remember Monica | Wouldn't the ground effect allow us to reduce airspeed as well ? | |
Oct 16, 2017 at 10:16 | comment | added | GdD | That is what I meant @Curd, I was oversimplifying things a bit as I didn't want to get too much into physics. | |
Oct 16, 2017 at 10:15 | history | edited | GdD | CC BY-SA 3.0 |
responded to comments.
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Oct 16, 2017 at 10:06 | comment | added | Curd | GdD: "momentum is related to the square of velocity of the aircraft": No, momentum is mass times velocity (p=mv; no squared here). You probably mean kinetic energy. It's one half times mass times velocity squared (E=1/2 mv²). | |
Oct 16, 2017 at 9:17 | history | answered | GdD | CC BY-SA 3.0 |