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Sep 16, 2015 at 20:24 comment added David Richerby @SteveH Sure but now things are backwards. You're deducing the physics from the behaviour of the aircraft (the fighter is more manoeuvrable so the MOI must decrease more than the torque), wereas you're supposed to be using the physics to explain the behaviour.
Sep 16, 2015 at 20:16 comment added Steve H @DavidRicherby For for given accereation rate (linear or rotational), less force (torque) is required for an object with a lesser mass (moment of inertia). Sure, the fighter's aileron may be creating less overall torque (due to a lesser arm and surface area), and if it is, then the MOI MUST be soooooo much lower than the airliner's that it results in an overall greater acceleration.
S Sep 16, 2015 at 18:11 history suggested Peter Mortensen CC BY-SA 3.0
Copy edited.
Sep 16, 2015 at 17:05 comment added David Richerby "For a rotational acceleration, moment of inertia takes the place of mass in the above equation" and force is replaced by torque. "Shorter wings reduce the moment of inertia" and also the potential torque from having a control surface at greater distance from the axis of rotation. It's not immediately obvious that these two competing factors resolve in a direction that increases, rather than decreases, acceleration.
Sep 16, 2015 at 16:59 review Suggested edits
S Sep 16, 2015 at 18:11
Sep 16, 2015 at 13:35 comment added Federico shorter wings reduce the moment of inertia not only, they also give much less rotational damping. moment of inertia will slow down the acceleration and the damping will slow down the rotation.
Sep 16, 2015 at 13:32 history answered Steve H CC BY-SA 3.0