Timeline for Is excess lift or excess power needed for a climb?
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 15, 2018 at 8:56 | comment | added | quiet flyer | In a stabilized climb (constant airspeed, constant direction of flight path through space), lift is LESS than weight. See my answer. | |
| Jun 1, 2015 at 11:40 | comment | added | Chris | @DanHulme: "You need to use more thrust to drive the cart with the wing attached, than you would if you took the wing away." Of course, the reason is additional drag, which dissipates to heat. I am fully aware that this violates conservation of energy. But remember that energy conservation is a "macro principle" that gets induced by more basic principles, e.g. mechanics. You have to give mechanical reasons to show that energy conservation is in place. | |
| Jun 1, 2015 at 11:19 | comment | added | Chris | Induced drag goes down when speed increases because wingtip vortices decrease at higher speed. | |
| Jun 1, 2015 at 9:53 | comment | added | Dan Hulme | @PeterKämpf Because the angle of attack is decreasing, you mean? That's a point. I'd hoped to keep the explanation simpler than that, but maybe I tried to make it too simple. | |
| May 31, 2015 at 17:54 | comment | added | Peter Kämpf | Believe it or not, induced drag goes down when speed increases. | |
| May 31, 2015 at 16:38 | comment | added | Waked | Induced drag in a steep climb is actually less than in a shallow climb, simply because lift is less (more of the net upwards force generated by thrust). By definition, Lift and Drag are perpendicular and parallel to the flight path (relative wind), not the earth horizontal plane. The increase in lift (and Di) s only momentary, to accelerate to create an upwards velocity as indicated by Peter Kämpfs answer | |
| May 31, 2015 at 12:55 | history | answered | Dan Hulme | CC BY-SA 3.0 |