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sophit
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lift force from the tail and lift increases quadratically with airspeed

Correct

That means that the faster jet will have a turning moment 11 times stronger than the slower plane?

No, because the aerodynamic force depends also on how many degrees the control surface is deployed, more or less in a linear manner. That means that instead of deploying the control surface of say 11° as you do at low speed, you deploy it only 1° i.e. 11 times less in order to compensate for the 11 times higher speed's contribution.

Changes in altitude ($\rho$), comprimibility effects (Mach > 0.3) amdand structural deformations modify this simple linear relationship but the main idea still holds i.e. at higher speed you need lower deflections.

lift force from the tail and lift increases quadratically with airspeed

Correct

That means that the faster jet will have a turning moment 11 times stronger than the slower plane?

No, because the aerodynamic force depends also on how many degrees the control surface is deployed, more or less in a linear manner. That means that instead of deploying the control surface of say 11° as you do at low speed, you deploy it only 1° i.e. 11 times less in order to compensate for the 11 times higher speed's contribution.

Changes in altitude ($\rho$), comprimibility effects (Mach > 0.3) amd structural deformations modify this simple linear relationship but the main idea still holds i.e. at higher speed you need lower deflections.

lift force from the tail and lift increases quadratically with airspeed

Correct

That means that the faster jet will have a turning moment 11 times stronger than the slower plane?

No, because the aerodynamic force depends also on how many degrees the control surface is deployed, more or less in a linear manner. That means that instead of deploying the control surface of say 11° as you do at low speed, you deploy it only 1° i.e. 11 times less in order to compensate for the 11 times higher speed's contribution.

Changes in altitude ($\rho$), comprimibility effects (Mach > 0.3) and structural deformations modify this simple linear relationship but the main idea still holds i.e. at higher speed you need lower deflections.

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sophit
  • 15.9k
  • 1
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  • 78

lift force from the tail and lift increases quadratically with airspeed

Correct

That means that the faster jet will have a turning moment 11 times stronger than the slower plane?

No, because the aerodynamic force depends also on how many degrees the control surface is deployed, more or less in a linear manner. That means that instead of deploying the control surface of say 11° as you do at low speed, you deploy it only 1° i.e. 11 times less in order to compensate for the 11 times higher speed's contribution.

Changes in altitude ($\rho$) and, comprimibility effects (Mach > 0.3) amd structural deformations modify this simple linear relationship but the main idea still holds i.e. at higher speed you need lower deflections.

lift force from the tail and lift increases quadratically with airspeed

Correct

That means that the faster jet will have a turning moment 11 times stronger than the slower plane?

No, because the aerodynamic force depends also on how many degrees the control surface is deployed, more or less in a linear manner. That means that instead of deploying the control surface of say 11° as you do at low speed, you deploy it only 1° i.e. 11 times less in order to compensate for the 11 times higher speed's contribution.

Changes in altitude ($\rho$) and comprimibility effects (Mach > 0.3) modify this simple linear relationship but the main idea still holds i.e. at higher speed you need lower deflections.

lift force from the tail and lift increases quadratically with airspeed

Correct

That means that the faster jet will have a turning moment 11 times stronger than the slower plane?

No, because the aerodynamic force depends also on how many degrees the control surface is deployed, more or less in a linear manner. That means that instead of deploying the control surface of say 11° as you do at low speed, you deploy it only 1° i.e. 11 times less in order to compensate for the 11 times higher speed's contribution.

Changes in altitude ($\rho$), comprimibility effects (Mach > 0.3) amd structural deformations modify this simple linear relationship but the main idea still holds i.e. at higher speed you need lower deflections.

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sophit
  • 15.9k
  • 1
  • 34
  • 78

lift force from the tail and lift increases quadratically with airspeed

Correct

That means that the faster jet will have a turning moment 11 times stronger than the slower plane?

No, because the aerodynamic force depends also on how many degrees the control surface is deployed, more or less in a linear manner. That means that instead of deploying the control surface of say 11° as you do at low speed, you deploy it only 1° i.e. 11 times less in order to compensate for the 11 times higher speed's contribution.

Changes in altitude ($\rho$) and comprimibility effects (Mach > 0.3) modify this simple linear relationship but the main idea still holds i.e. at higher speed you need lower deflections.

lift force from the tail and lift increases quadratically with airspeed

Correct

That means that the faster jet will have a turning moment 11 times stronger than the slower plane?

No, because the aerodynamic force depends also on how many degrees the control surface is deployed, more or less in a linear manner. That means that instead of deploying the control surface of say 11° as you do at low speed, you deploy it only 1° i.e. 11 times less in order to compensate for the 11 times higher speed's contribution.

lift force from the tail and lift increases quadratically with airspeed

Correct

That means that the faster jet will have a turning moment 11 times stronger than the slower plane?

No, because the aerodynamic force depends also on how many degrees the control surface is deployed, more or less in a linear manner. That means that instead of deploying the control surface of say 11° as you do at low speed, you deploy it only 1° i.e. 11 times less in order to compensate for the 11 times higher speed's contribution.

Changes in altitude ($\rho$) and comprimibility effects (Mach > 0.3) modify this simple linear relationship but the main idea still holds i.e. at higher speed you need lower deflections.

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sophit
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