Those diagrams, versions of which have been reproduced in many different flight training "ground school" materials, including some published by the FAA, are extremely misleading, and contain errors and/or omissions, depending on exactly what each force vector is supposed to represent.
Rather, slips and skids are could be said to be characterized by an imbalance between the pseudoforce called "centrifugal force", and the horizontal component of the wing's lift force. (This isn't the most simple or most intuitive definition of a slip or skid, but it is a valid one.)
If the vectors labelled "HCL" are supposed to represent the horizontal component of the net aerodynamic force generated by the aircraft, including the horizontal component of the aerodynamic sideforce generated by the airflow striking the side of the fuselage, then they are drawn incorrectly. They should be mirror images For a given bank angle, the horizontal component of the vectorsnet aerodynamic force generated by the aircraft is larger in a skidding turn than in a coordinated turn, and is smaller in a slipping turn than in a coordinated turn. If the vector labelled "total lift" is supposed to represent the total aerodynamic force generated by the aircraft, including the sideforce contribution from the airflow striking the side of the fuselage, then the coordinated turn is the only case where the "total lift" vector should be exactly "square" to the wingspan. In all cases the "centrifugal force" vector should be a mirror image of the vector representing the horizontal component of the net aerodynamic force generated by the aircraft.2
On the other hand, if the vectors labelled "HCL", "VCL", and "Total Lift" are only supposed to represent the horizontal, vertical, and total components of the horizontal component of the wing'swing's lift vector, then they are drawn correctly, but the diagrams arebecome very misleadingconfusing because the vector representing the horizontal component of the aerodynamic sideforce generated by the airflow striking the side of the fuselageaerodynamic sideforce generated by the airflow striking the side of the fuselage has been entirely omitted. Also, if In this case the vectors labelled "HCL" are only supposed to represent"centrifugal force" should still appear as described in the horizontal component of the wing's lift vectorabove paragraph, then by logical extensionbut in the vectorsslipping and skidding cases, the vector labelled "VCL" must"HCL" will no longer be intended to only representa mirror image of the vertical component of the wing's lift vectorvector labelled "centrifugal force". For a given bank angle, notthe wing's total lift vector, and therefore the horizontal and vertical componentcomponents of the net aerodynamic force generated by the aircaft. In which case the vectors labelled "VCL" shouldwing's lift vector, are all slightly notsmaller be all the same length, because in a slipslipping turn than in a coordinated turn, because the aerodynamic sideforce fromgenerated by the airairflow striking the side of the fuselage includes an upward vertical component which supports somea small portion of the aircraftaircraft's weight.3 Similarly, in a skidding turn, the wing's total lift vector, and reducestherefore the horizontal and vertical force thatcomponents of the wing must generatewing's lift vector, whileare all slightly larger than in a skidcoordinated turn, because the aerodynamic sideforce fromgenerated by the airairflow striking the side of the fuselage includes a downward verticalcontains an earthward component which increase the vertical force that most be opposed by the wing must generatewing's lift vector. These differences should be apparent in the vectors labelled "VCL" and "Total Lift" as well as the vectors labelled "HCL", and the vector labelled "Total Lift" should be "square" to the wingspan in all three cases.
Obviously the diagrams would be greatly improved by changing to an airmass-based reference frame rather than an aircraft-based reference frame, so that the "centrifugal force" vector could be entirely discarded, and by also including by the aerodynamic sideforce vector generated by the air striking the side of the fuselage. There's no need to break things into horizontal and vertical components,-- just show the wing's lift vector and the aerodynamic sideforce vector from the airflow striking the side of the fuselage. These two vectors are oriented perpendicular to each other. In a coordinated turn, there is no airflow striking the side of the fuselage, so the aerodynamic sideforce vector is zero, so the net aerodynamic force acts "straight up" in the aircraft's reference frame. In a slip or a skid, the aerodynamic sideforce vector is not zero, and so the net aerodynamic force does not act "straight up" in the aircraft's reference frame. End of story. (If desired, an "apparent load" vector could be added, which would always be the mirror image of the vector sum of the wing's lift vector and the aerodynamic sideforce vector from the airflow striking the side of the fuselage. Only in the case of the coordinated turn, where aerodynamic sideforce is zero, would the "apparent load" vector be exactly "square" to the wingspan. And now-- keeping in mind that the weight vector makes no contribution to the "apparent load" vector-- we understand why the inclinometer ball behaves as it does in slipping, skidding, and coordinated turns. And we've come to this understanding without ever invoking some sort of hypothetical "imbalance" between "centrifugal force" and some other force. It all boils down to the question of whether the airflow is, or is not, striking the side of the fuselage and generating an aerodynamic sideforce vector.)
Because when include the pseudoforce called "centrifugal force" in our vector diagrams, we are using an aircraft-based reference frame rather than an airmass-based reference frame or ground-based reference frame. Since the aircraft can't accelerate relative to itself, the net force in the aircraft-based reference frame will alwaysalways be zero, whether the aircraft is turning or not. In the aircraft-based reference frame, the fact that the centrifugal force vector exists at all is actually evidence that the aircraft is turning. You can see from the preceding parts of this answer that the author of this answer feels that But for teaching purposes, using the aircraft-based reference frame (and therefore including the "centrifugal force" vector whenever the flight path is not linear) is arguably an inferior approach to using the airmass-based reference frame (and therefore not including any "centrifugal force" vector.)
- In this answer, when we talk about "horizontal", we mean as seen looking at the aircraft in a head-on view. We're not referring to fore-and-aft forces such as thrust and drag.
In this answer, when we talk about "horizontal", we mean as seen looking at the aircraft in a head-on view. We're not referring to fore-and-aft forces such as thrust and drag.
Note that in the diagrams attached to the question, the illustrator chose to make the "total load" vectors in the "skidding turn" and "coordinated turn" identical, and to make the "HCL" (horizontal component of lift) vectors in the "slipping turn" and "coordinated turn" identical. That's all kind of random and makes no sense.
For an extreme case, consider sustained linear "knife-edge" flight at a 90-degree bank angle-- here the aerodynamic sideforce from the airflow striking the side of the fuselage is doing all the work of supporting the aircraft's weight, and the wing's lift vector is zero.