I'm studying the Bell 206 Maintenance manual to understand how the pilot's control inputs get converted to swash plate movements.
This diagram seems to explain the cyclic well, but I can not figure out how the lateral stick movement is transformed.
Here is an example of how the crank mixer is operated by the cyclic (Y bar 9)
The forward-aft movement of 12 (the stick) causes member 10 to rock back and forth, moving 9 back and forth, which operates the mixing cranks at the end (connected to 7 and 8).
However, it looks like the stick can't mover laterally at all, since 10 can't move laterally (?) I can't figure out even why 10 has a provision for motion in the vertical plane in the first place.
Perhaps I'm misunderstanding how 12 moves? I'm assuming it pivots around the base (15).