How does a pilot flying the scooping maneuver in a CL415 firefighting plane deal with the changing forces from taking on such a large mass of water (nearly 50% of the plane's own mass) as quickly as these planes do?
Some basic math indicates that the scooping maneuver would generate $F=\dot{m}v = 18.4\ \mathrm{kN}$ of additional backwards force just from accelerating the $\dot{m} = \frac{\Delta m}{\Delta t} = \frac{6140\ \mathrm{kg}}{12\ \mathrm{s}} = 512\ \mathrm{kg/s}$ of scooped water up to the plane's $v = 36\ \mathrm{m/s}$ scooping speed.
Or using a different calculation, with no additional thrust added to compensate, the plane would slow from 70 to about 50 knots from taking on the water. Plus, there's other forces generated here too — a downward force from accelerating the water vertically to lift it into the plane's tank, probably a pitch-down torque from the scoop placement, the additional weight from the changing mass, and also just the hydrodynamic drag forces that seaplanes also deal with landing or taking off.
Some of the control inputs seem clear, like needing to throttle up and probably pitch up slightly, but how does the pilot determine the adjustments to make here, and how do they coordinate the timing for making these adjustments?
Also, how does adjusting trim for the empty vs full states work? I'm imagining that there'd be some way to mark down separate trim settings for empty vs full and then use that to quickly switch to the appropriate trim after scooping or dumping the load, but is this done manually or is this automated in some way?