Wikipedia provides an explanation of the lift force in terms of flow deflection and Newton's laws, emphasis mine:

An airfoil generates lift by exerting a downward force on the air as it flows past. According to Newton's third law, the air must exert an equal and opposite (upward) force on the airfoil, which is lift.

The airflow changes direction as it passes the airfoil and follows a path that is curved downward. According to Newton's second law, this change in flow direction requires a downward force applied to the air by the airfoil. Then Newton's third law requires the air to exert an upward force on the airfoil; thus a reaction force, lift, is generated opposite to the directional change. In the case of an airplane wing, the wing exerts a downward force on the air and the air exerts an upward force on the wing.

The downward turning of the flow is not produced solely by the lower surface of the airfoil, and the air flow above the airfoil accounts for much of the downward-turning action.

In what way does the air flow above the airfoil account for much of the downward-turning action of the air flow below the airfoil?


1 Answer 1


The answer is buried in the linked Wikipedia article if you read it carefully a few times.

In a nutshell, at least in my interpretation, the "zone of suction" you might call it, the Bernoulli effect low pressure region above the airfoil, induces air outside the zone to accelerate toward it; to "fill the void". On a zone of suction that is moving, like the top of the wing, it means that a large region of the air stream above the wing wants to accelerate toward the zone, which being below, means that the net result is the a large package of air is induced to move downward in response to the wing's passage below it.

Maybe half or more of the total package of air that is redirected downward is above the wing. This air is being induced to move by "pressure trickery" as opposed to being shoved down directly by the pressure wave of physical wing's passage like the air below. A water ski works by deflecting only the fluid below it. A wing works by deflecting the gasious fluid below, and also inducing the gaseous fluid above to join in by careful management of pressures.

This is partly why disruption of the flow above has a more drastic effect than disruption of the flow below - spoilers go on top instead of underneath. Air below is just being physically deflected; the air above, for quite some distance, is being "coaxed" to be pulled down toward the low pressure region, and if you disrupt the low pressure region, all of the air that was ready to be induced to move down doesn't have to, and you lose most of your Newtonian force reaction.

The result is that this contraption flies fine with all that junk obstructing the flow under the wing, but if you put it all on top, it would never get off the ground.

enter image description here

  • $\begingroup$ The tricky part is explaining why the low pressure region is there. You can't you Bernoulli's principle, because you don't yet know there should be higher speed either. The real reason is that air “does not like” to navigate sharp corners, so it prefers sticking to the surface to creeping around the trailing edge—until the slope is too steep, when the wing stalls. $\endgroup$
    – Jan Hudec
    Feb 1, 2021 at 7:44
  • $\begingroup$ What would be a good shorthand label to use in place of Bernoulli effect? $\endgroup$
    – John K
    Feb 1, 2021 at 15:15
  • $\begingroup$ "Pressure trickery", or "bait and switch", can be used. The leading edge splits the air flow up and down much like the bow of a ship. The low pressure area is created because the wing moves past the impact zone faster than the air moves down to close the vacuum. This phenomena (including stall buffet turbulence) can be observed at the stern of a common boat. As it moves faster, the turbulence separates from the back and forms a neat "downwash" off both sides, resulting in a "V" wake (that water skiers love). The vacuum above the wing is formed by the wing outrunning its turbulence. $\endgroup$ Feb 2, 2021 at 1:29

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .