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I was flying through this section in the ASA test prep book, I thought I had mastered this E6B. But this has me stumped:

Question 2222

Figure 71

I can’t do the math to figure out how many knots I’ve traveled. But in the answer it has me plotting a course of 280 (100 + 180) from the departure point. I cannot figure out for the life of me where they got this course.

I see that the winds are from 100 in the winds aloft, but I can’t imagine how I get a 100+180 course from that. I feel like I’ve missed some major concept.

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    $\begingroup$ If the wind is coming from 100 degrees, which direction will the plane be blown? $\endgroup$
    – StephenS
    Nov 22, 2020 at 20:42
  • $\begingroup$ Ok, that helps. 280 is opposite 100. Got it. But isn’t it still making a lot of assumptions like no wind correction and such? $\endgroup$
    – rbsc
    Nov 22, 2020 at 20:51
  • $\begingroup$ I'm not sure I understand the question. You didn't mention which heading or course the question asks you to fly from the airport. E.g. heading 100 would take you directly into the wind; 280 would take you directly away from it etc. Or are you just asking about the effect of the winds only, and not what they mean for the final track of the aircraft? If you could quote the entire question I think it would be a lot clearer. $\endgroup$
    – Pondlife
    Nov 23, 2020 at 17:02
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    $\begingroup$ @Pondlife That had me baffled too until I saw this is for the LSL (Light Sport-Lighter Than Air) test. $\endgroup$
    – StephenS
    Nov 24, 2020 at 1:49
  • $\begingroup$ I didn't notice LSL, but with airspeed matching wind I was just starting to question whether this was for a balloon! @rbsc, did you realize this?! $\endgroup$ Nov 24, 2020 at 2:36

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First of all, make sure you’re only doing the questions that will actually be on the test you’re taking. This specific question is only for the LSL question bank, so unless that’s what you need, forget it and move on.

In a balloon, you will be carried by the winds aloft. If the wind is from 100@8, then your track will be to 280@8.

First, use your protractor to draw a track line on a track of 280 from the point of departure. This shows your balloon’s track over the ground.

Next, multiply 8 by the (decimal) number of hours you will be in the air, and then use your scale to mark that distance along the track line. That’s how far your balloon will have traveled at the specified time.

No need for an E6B here.

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    $\begingroup$ Son of a.. No. I sure did not realize this was a balloon question. Makes so much more sense now. Face palm. Thanks to you all! $\endgroup$
    – rbsc
    Dec 5, 2020 at 15:04

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