I was looking up V-speeds for C172. I don't have easy access to an official copy of the POH, but online I found:

  • $V_y$, best rate of climb speed (at sea level): 76 KIAS (p22)
  • $V_{glide}$, maximum glide speed: 65 kts (p15).

But I always thought that $V_y$ is the speed for highest L/D, which should give both highest rate of climb and lowest rate of descent, and that longest glide is achieved by flying slightly faster than that, because drag grows with square of speed, and therefore it initially grows slower than speed above the minimum drag point.

So why is the $V_{glide}$ quoted lower than $V_y$?

  • $\begingroup$ This question contains a misconception. The glide angle can be expressed as a simple trigonometric function of the L/D ratio, and as a result,the flattest glide in still air DOES in fact occur at the airspeed that yields the greatest L/D ratio. The airspeed for minimum sink rate will always be lower than this. This observation doesn't actually answer why Vy is apparently higher than Vglide in the specific case explored in the question, but it does point out something that could be improved in the question (if it's not too late to do so without invalidating an existing answer.) $\endgroup$ Commented Mar 9, 2020 at 1:27
  • $\begingroup$ @quietflyer, indeed, vertical speed times gravity constant is power, but drag is force. Angle times gravity is force, which would suggest best L/D should match best angle. That does not seem to match the common wisdom though. $\endgroup$
    – Jan Hudec
    Commented Mar 9, 2020 at 13:28
  • $\begingroup$ @quietflyer, well, I've acquired the idea that max L/D (sans the propeller effects; those complicate the matter a lot) is where best rate of both climb and descent is somewhere along the way, but I don't remember exact reference (it had to be on this site though). $\endgroup$
    – Jan Hudec
    Commented Mar 9, 2020 at 15:02
  • $\begingroup$ … it might have been me misinterpreting the power curve somewhere though. $\endgroup$
    – Jan Hudec
    Commented Mar 9, 2020 at 15:04
  • $\begingroup$ Maybe my new answer will help. Forgetting about propeller effects, we would say that max glide angle occurs at max L/D airspeed which is essentially the airspeed where Drag is minimized. The minimum sink rate airspeed is always slower than this point. The minimum sink rate airspeed is (forgetting about propeller effects) the airspeed where the least power is required to maintain level flight. If the power available from the propulsion system were independent of airspeed, the minimum sink rate airspeed would also yield the max rate of climb. $\endgroup$ Commented Mar 9, 2020 at 15:10

4 Answers 4


The best glide speed is the speed where tangent line from the origin (zero horizontal and vertical speed) touches power curve (for unpowered airplane).

Best rate of the climb is the highest point of the power curve.

When we start with unpowered airplane, the direct equivalent of best rate of climb is lowest rate of sink. The speed for lowest sink will be clearly lower than the best glide speed.

If we would assume that aircraft engine is a magical device, which simply adds some fixed amount of mechanical energy to the airplane regardless of what, then the "powered" power curve would be simply the "unpowered" one shifted up in the graph. Under such assumptions the speed for best climb would be the same as the speed for minimum sink and in both cases lower than best glide speed.

Idealized power curve shift

Nevertheless mentioned Cessna converts fuel to mechanical energy through not-so-magical fixed pitch propeller which pushes some amount of air around. Such propeller would be typically optimized for highest efficiency at the cruise speed, so with decreasing speed the amount of available mechanical energy dereases. Which results in changed shape of power curve and maximum point moves towards higher speeds compared to the "unpowered" power curve.

Real change of power curve with engine running

This shift can be high enough that Vy ends up higher than Vg.

The Vy is always higher than the speed for the best climb angle, because these two speeds are found on the same (max power) power curve. For the same reason best glide speed will be always higher than speed for minimum sink. But speeds for best rate of climb and for the least sink does not need to be the same because of effects of real propeller.

For related images and more information, have a look at great online text See How It Flies.

  • 9
    $\begingroup$ +1 for whipping out your pen in two colours no less, making charts, and taking pics with your phone. Well done. $\endgroup$
    – John K
    Commented Feb 1, 2020 at 1:08
  • $\begingroup$ To add: Vx is the speed for the steepest climb whist Vg is the speed for the shallowest glide (best glide speed). Flying at Vx or Vg yields the best angle. Flying at Vy yields the best rate of climb at a more shallow climb angle. $\endgroup$
    – Jan
    Commented Feb 1, 2020 at 10:17
  • $\begingroup$ Re "propeller would be typically optimized for highest efficiency at the cruise speed", there are also fixed-pitch propellors that are optimized for climb, which you might see on bush planes and the like. $\endgroup$
    – jamesqf
    Commented Feb 1, 2020 at 17:54
  • $\begingroup$ This is great answer but it could be further improved. In the first sentence when you mention the "power curve for an unpowered airplane", you could make it clear that what you are really talking about is a graph of airspeed versus sink rate. You could then explain that this also equates to power-required curve if we want to add power to make that airplane maintain level flight. You could also point out that the real essence of the answer is "the power-available curve is not a straight horizontal line, and therefore the shape of the power-required curve is not the only factor at play." $\endgroup$ Commented Mar 9, 2020 at 13:49

The fact that best climb speed is above best glide speed indicates two things:

  1. The airplane has a fixed pitch propeller.
  2. Its power at climb speed is limited by engine RPM limits.

Normally, best climb for propeller aircraft should be when the ratio ${\frac{c_L^3}{c_D^2}}$ reaches its optimum which is at higher lift coefficients than best glide. But that not only assumes a quadratic polar but also a constant propeller efficiency over speed.

A fixed-pitch propeller has its pitch normally selected for cruise so in climb the aircraft will fly slower than what the propeller is designed for. At that speed, propeller efficiency increases almost linearly with speed, as can be seen in the plot below. To create it, I simply calculated the angle of attack and dynamic pressure at 75% span and with that approximated the thrust. Next, I used the same figures for calculating the drag on the blades and thus the power required to drive them at that speed. Dividing thrust times speed by that power produced the efficiency graph. Note that I used the advance ratio (forward speed divided by circumferential speed at the tips) for the X-axis.

Propeller Efficiency over advance ratio for different pitch angles.

The linear increase in efficiency will in effect produce constant thrust over speed, so the best climb speed should be the same as for turbojets.

But that again makes assumptions which might not hold in reality. Obviously, it assumes constant power and prop RPM over speed. If the prop cannot absorb the available power at lower speed, the engine has to be throttled back in order to avoid overspeeding it. I would expect that you cruise that Cessna at a more forward throttle position than what is possible in climb.

Now we have a condition where power and thrust both increase with speed, so the best climb speed is above best glide speed.

Thank you for pointing out this seeming contradiction! It made me reflect my assumptions in deriving best climb speeds and helped me to refine my conclusions.

  • $\begingroup$ C172 climbs at Vy on full throttle. At higher speeds (incl. cruise) it has to be throttled back. $\endgroup$
    – Zeus
    Commented Feb 11, 2020 at 0:18
  • $\begingroup$ @Zeus Then why would v$_y$ be above best glide speed? The accepted answer does not explain this – maybe you can? What is the RPM in climb? $\endgroup$ Commented Feb 11, 2020 at 7:51
  • $\begingroup$ There are different versions, some (cruise optimised) have redline at 2300 RPM, some at 2700. At Vy (76-79 KIAS), both are a bit short of redline (these aircraft are very forgiving and you need to work or be really negligent to exceed limits). They start to overspeed (at full throttle) above 85-90 KIAS. So, in our speed range of interest it does appear to be power-limited. But cruise speed (~110 KIAS) is outside of this range. $\endgroup$
    – Zeus
    Commented Feb 11, 2020 at 8:14
  • $\begingroup$ I think there is a typo in the second sentence of the answer. You stated that best rate of climb should occur at max (Cl/Cd)^(3/2). Didn't you mean to say the maximum value of (Cl^3 / Cd^2) ? $\endgroup$ Commented Mar 9, 2020 at 16:20
  • $\begingroup$ @quietflyer: Thank you for your diligent proofreading. Corrected. $\endgroup$ Commented Mar 9, 2020 at 16:27

If we take the curves for power required and power available, the best glide is the airspeed at which a straight line from the origin is tangent to the power required curve.

And the speed for best rate of climb is the airspeed at which the tangents to the power required and power available curves are parallel...

From 'Theory of Flight', by Richard von Mises (Dover Books):

enter image description here

Hence, with properly shaped curves, and in theory at least, the best climb speed might be higher than the best glide speed...

  • $\begingroup$ That does not explain why, it only repeats what has been said before. $\endgroup$ Commented Feb 11, 2020 at 7:52
  • $\begingroup$ It explains how, and that's what the OP asks... $\endgroup$
    – xxavier
    Commented Feb 11, 2020 at 8:17

Good answers have been posted, but here is another spin that adds a few other important points, while omitting for brevity some of the other points that have already been made. This answer also clears up a misconception in the original question about the significance of the Lift/Drag ratio in relation to the airspeed for best glide ratio and the airspeed for minimum sink rate.

For unpowered flight, we can draw a curve of sink rate versus forward (horizontal) speed. (Some other answers have referenced this as a "power curve".)

In unpowered, non-turning flight, Lift, Drag, and Weight form a closed vector triangle. Since the Lift and Drag vectors act perpendicular and parallel to the flight path, respectively, this closed vector triangle "anchors" the direction of the flight path in space with respect to the Weight vector. In other words, if we know the direction of the flight path with respect to the ground-- i.e. the glide angle-- then we know the L/D ratio, and vice versa. In fact, in unpowered, non-turning flight, the glide ratio (horizontal distance travelled per unit of altitude lost) is always exactly the same as the Lift/ Drag ratio. This means that glide angle = arctan (D/L).

This means that the smallest (i.e. flattest) glide angle takes place at the minimum D/L ratio.

Starting with a graph of sink rate versus horizontal (forward) speed, there's an easy way to find the "glide ratio", or horizontal distance traveled divided by altitude lost, for any given horizontal speed. It's simply the slope of the line drawn from the origin of the graph to the point in question. The highest possible "glide ratio"-- which corresponds to the smallest possible "glide angle"-- is simply the point where a line drawn in this manner is exactly tangent to the curve of sink rate versus forward (horizontal) speed. And as we've already noted, in unpowered flight, the "glide ratio" at any given forward (horizontal) speed is also exactly the same as the L/D ratio at that speed, so the highest possible glide angle also occurs at the forward (horizontal) speed that gives the highest L/D ratio or lowest D/L ratio.

Note that this tangent point will always occur somewhat to the right of the point of minimum sink rate. The speed for the flattest glide angle (best glide ratio) is always somewhat faster than the speed for the minimum sink rate.

For reasonably flat glide angles, forward (horizontal) speed is nearly the same as airspeed. Therefore, for most practical purposes, our graph of sink rate versus forward (horizontal) speed can be re-labelled as a graph of sink rate versus airspeed.

Recall again that the smallest (i.e. flattest) glide angle takes place at the minimum D/L ratio. For reasonably flat glide angles, as we vary airspeed, lift remains nearly equal to weight, so nearly all the variation in the L/D ratio (i.e. the glide ratio) is due to variation in Drag, not Lift. (Don't misinterpret this to mean that the lift coefficient stays nearly constant as the airspeed varies-- it does not.) This means that for reasonably flat glide angles, it is a close approximation of reality to say that the airspeed that yields the minimum D/L ratio and the smallest (flattest) glide angle, is also the airspeed the yields minimum Drag force, as measured in pounds or Newtons. (Don't misinterpret this to mean that the drag coefficient is minimized at this airspeed-- it is not.)

Therefore, at the forward (horizontal) speed, and the airspeed, that yields the minimum sink rate, the Drag force is actually higher than it is at the airspeed that yields the maximum glide ratio (minimum glide angle). Here's one way to think about this-- loosely speaking, the Drag force determines the steepness of the "slope" that the aircraft is gliding down. But travelling more slowly along a slightly steeper slope will give a lower rate of descent than travelling more quickly along a slightly flatter slope.

What happens if we start with a sink rate-versus-airspeed curve generated by an aircraft with the prop removed, or with the engine generating just enough power so that the prop is contributing exactly zero net thrust, and then we change the conditions so that the prop is windmilling and forcing the engine to turn? The sink-rate-versus-airspeed curve will be degraded-- the sink rate for any given airspeed will be increased, but more so at higher airspeeds. The point of minimum sink rate, and the point of flattest glide, will both be shifted toward the left, toward lower airspeeds.

To maintain level flight, the motor has to supply enough power to offset the sink rate that the aircraft would experience if the motor were contributing zero net thrust. More precisely, the power requirement is equal to sink rate times weight. Therefore our graph of sink rate versus airspeed can also be thought of as a graph of "power required" versus airspeed. However, to look at how an aircraft will perform when we add power, the appropriate "power required" graph would be one generated with the propeller removed (or with just enough engine power applied to produce exactly zero thurst), not one generated with the propeller windmilling.

At any given airspeed and throttle setting (e.g. wide-open throttle), the sink rate or climb rate will be due to the difference between the "power required" and the "power available". At the wide-open throttle position, if the graph of "power available" versus airspeed were a simple horizontal line, then the shape of the "power required" graph-- which is the sink rate versus airspeed graph-- would entirely determine the the airspeed for maximum climb rate. In this case, the maximum climb rate would always occur at the power-off minimum sinking speed-- at least so long as we were talking about a sink rate versus airspeed graph that was created with the prop removed or idling in the zero-thrust condition, rather than windmilling.

However, the shape of the power-available curve is not a simple horizontal line, especially in the case of an aircraft with a fixed-pitched prop. It will typically have a peak that is located well to the right of (i.e. higher than) the airspeed for the best glide speed or max L/D ratio, which biases the speed for best climb rate toward a higher airspeed.

In summary, the best climb rate occurs at a higher airspeed than the flattest glide angle because--

1) the airspeed for flattest glide angle is measured with the prop windmilling, not with the engine applying just enough power to generate a zero-thrust condition. This shifts the sink rate-versus-airspeed curve toward the left of where it would be if it were generated with the motor creating just enough power so that the prop were contributing neither thrust nor drag.


2) the power-available versus airspeed curve is not a flat horizontal line, but rather peaks at an airspeed that is higher than the airspeed corresponding to the flattest glide angle. With a fixed-pitch prop, this is typically is true even if we are making a comparison to the aircraft's performance at the airspeed that gives us the flattest glide angle with the engine providing enough power to generate a zero-thrust condition, and it is even more true if we are making a comparison to the aircraft's performance at the airspeed that gives us the flattest glide angle with the engine windmilling. This biases the best climb-angle and best climb rate airspeeds toward the right (toward higher airspeeds) compared to what we'd see if the propulsion system delivered the same amount of power at all airspeeds.

Two final notes--

A) All discussions of glide angle in this answer are with respect to the airmass, not the ground. In other words, if we're measuring our glide angle with respect to the ground, then we're doing so in zero-wind conditions. Optimizing the choice of airspeed to fly to get the best possible glide angle over the ground various wind conditions is an interesting topic, but one that is beyond the scope of this answer.

B) This answer has only touched briefly on the subject of lift and drag coefficients. It may interest the reader to know that the following are true, using "Cl" to represent the lift coefficient and "Cd" to represent the drag coefficient:

i. The airspeed for max L/D ratio is also the airspeed where the ratio of Cl/Cd is maximized.

ii. The airspeed that yields the minimum sink rate is also the airspeed that yields the maximum value of (Cl cubed) / (Cd squared).

iii. The expressions (Cl/Cd) and (L/D) are equivalent, but the expressions ((Cl cubed) / (Cd squared)) and ((L cubed) / (D squared)) are not equivalent.


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