This question is from the PPL questions book, navigation part.

Given: QDM: 279° VAR: 5° W DEV: 5° E
The QDR equals...

  • $\begingroup$ What have you tried so far? Is there are specific part you don't understand? $\endgroup$ – fooot Apr 29 '19 at 22:08
  • $\begingroup$ Correct me If I'm wrong. I know that the DEV part is used to get the Magnetic Heading and what I should do is subtract 5 degrees from the given QDM but what should I do with VAR which is given. Is that about the Course Heading? Confused. $\endgroup$ – Canberk Apr 29 '19 at 22:16

QDM is magnetic bearing to station, QDR is magnetic bearing from station so VAR and DEV are here only to confuse you; the QDR is opposite of QDM so the answer is 099.

Notice that QDR and QDM do not depend on aircraft’s heading or flight path, they are only dependent on A/Cs location relative to the station.

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