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I have a reasonable understanding of what a V-n diagram shows and what the envelope and the boundaries mean. However, the question I have is how does the weight of the aircraft specifically affect the diagram?

I know that reducing the weight will mean a lower load factor and therefore potentially more manoeuvrability. But is there a mathematical way of showing this? Also, how does the weight relate to lift? Again, lower weight means less lift is needed. But how does that specifically affect the V-n diagram?

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    $\begingroup$ Highly related -- aviation.stackexchange.com/a/13140/34686 $\endgroup$ Commented Apr 17, 2021 at 16:34
  • $\begingroup$ I recommend "Aerodynamics for naval aviators" which is now available as a free PDF. (As I recall it is hosted on the FAA website.) It covers this issue and with better reliability then any answer you will get here. Generally aircraft are complex structures and each sub component has its own limits, and then you must define "maneuverability" as it pertains to engineering or to operation, using strength or aerodynamic limits. This is all further complicated by some rampant misinterpretations of an FAA reg regarding Va and required *design load factor for the old arbitrary normal/utility cat.. $\endgroup$
    – Max Power
    Commented Jan 19, 2022 at 23:43

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When an aircraft is heavier (say wing tanks or fuselage tanks full of fuel), a given amount of pounds of force generated by the wings results in a lower G-load and thus less force on components of fixed weight, like the battery or engine(s). Therefore the mounts holding these parts of the aircraft in place are subjected to less stress. Therefore the maximum amount of force the wing can be permitted to exert --measured in pounds or Newtons, not G's-- can be raised-- again assuming it's the stress on things like the motor mounts, etc that we're concerned about-- and that's why the maneuvering speed (Va) in many aircraft increases as aircraft weight is increased. (Below maneuvering speed, the wing will stall before generating some critical amount of force that has been judged by the designer to be too much.)

A simpler way to state this is that if we are setting the maneuvering speed to protect the mountings of items of fixed weight, then all that matters is the max G-load that we allow the aircraft to develop. When the aircraft is heavier, for any given G-load, the stall speed will occur at a higher airspeed. Maneuvering speed is the speed where the aircraft will stall before exerting so much force that it damages the structure. So if we are setting the maneuvering speed to protect the mountings of items of fixed weight by not allowing the aircraft to exceed some given G-load, then we can increase the maneuvering speed as we increase the weight of the aircraft.

On the other hand, if were worried about ripping the wings off the fuselage-- if that was the limiting factor in setting our limiting speed-- then it wouldn't make any sense to raise our limiting speed as we increase aircraft weight, at least if all the increased weight was going into the fuselage. In a simplified case where the weight of the wing is negligible compared to the weight of the fuselage, when the wing is generating X pounds of lift, the same amount of force is being transferred from the wing to the fuselage, regardless of how heavy the fuselage is and therefore what the G-load is. If the weight of the wing is not negligible compared to the weight of the fuselage, then adding weight to the fuselage means a lower percentage of the wing's lift force will be "absorbed" by the wing itself, and for a given X pounds of lift force generated by the wing, the force exerted by the wing on the fuselage, and the stress on the wing-fuselage connection, will go up as we increase the aircraft weight. In such a case, if the wing-fuselage connection is our critical concern, then it would make sense for the maneuvering speed to go down as the aircraft weight is increased. On the other hand if the extra weight is going into the wing (fuel, external stores hung from the wings) then for a given X pounds of lift generated by the wing, some of the wing's lift force will be "absorbed" by this weight and the total G-load in any given situation will be less and there will be less force transferred from the wing to the fuselage and less stress on the wing-to-fuselage mounting, so again it would make sense to raise the maneuvering speed as we increase the aircraft weight, if areas such as the wing-to-fuselage mounting are the critical concern.

Similarly, if more of the weight is distributed along the wingspan, the bending stress on the wing spars will be less, for a given total force in pounds generated by the wing. So if the wing spars are the critical component of concern that governs our choice of maneuvering speed, then if we increase weight by adding it to the wing, the maneuvering speed should go up, but if we increase weight by adding it to the fuselage, the maneuvering speed should go down.

So, it's complicated. The simplest case is when the limiting concern is the stress on the mountings of items of fixed weight, such as motor mounts, battery brackets, etc, as described at the start of this answer. My understanding is that that is in fact this most common case and explains why on the Vn diagram, the maneuvering speed typically goes up as the aircraft weight goes up. Again, in this case we are simply setting a maximum allowable G-loading.

"Maneuvering speed" is not explicitly shown on the figure linked in the question, but generally, it occurs at the point where the line representing the max G-load allowable meets the curved left edge of the envelope representing the stall, with some extra safety margin added. The discussion above of whether the maneuvering speed Va should be raised or lowered as we add weight to the aircraft, depending on where we are adding the weight, is exactly equivalent to a discussion of whether we should raise or lower the limiting G-load, or neither, as we add weight to the aircraft. Note that on the V-n diagram, adding weight to the aircraft will shift the curved left edge of the envelope representing the stall further to the right. You can see how, if our goal is simply to set the maneuvering speed in a way that prevents the aircraft from exceeding some fixed maximum allowable G-loading, then an increase in weight will automatically change the V-n diagram in a way that increases the maneuvering speed in proportion to the square root of the increase in the weight. However, if the goal is to limit the stress on the wing spars, or the wing-to-fuselage connection, then the situation may be completely different, depending on where we are adding the weight.

(The diagram linked in the answer doesn't show this, because it doesn't show the stall speed for different weights. Rather, it shows a change in IAS stall speed with altitude, which is likely related to Mach effects, and not something that we have to concern ourselves with in lower-performance aircraft.)

Related ASE questions and answers--

Q: What is Vg in this VG diagram?

A: What is Vg in this VG diagram?" -- in this case the aircraft (glider) was assigned a higher Vg, the maximum speed allowed in gusty conditions, as well as a higher Vne, when it was carrying less weight. The opposite of what we often see in regard to the maneuvering speed, Va, in light airplanes. So-- as indicated in the present answer-- "it's complicated".

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  • $\begingroup$ Also highly related -- aviation.stackexchange.com/a/42614/34686 $\endgroup$ Commented May 11, 2021 at 18:44
  • $\begingroup$ (fixed typo after "community" bumped up to top of stack-- not sure why "community" action not showing in edit history) $\endgroup$ Commented May 13, 2022 at 14:36
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    $\begingroup$ +1 for the detailed analysis. It's interesting to note that in the F-4J example I given in my answer, putting weight on the wing by e.g. loading wing stores causes a reduced g-limit compared to loading centerline stores, with the same gross weight, as wing bending considerations might be out-weighted by other factors, such as the g-limit of the store itself. But the case can be completely different with heavier aircraft, as wing bending could be more of a problem. $\endgroup$
    – LJQCN101
    Commented May 6 at 10:43
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Well, answering your first question, the airplane weight does not really affect the V-n diagram because this diagram is developed knowing the structural forces that the airplane can take without being damaged.

Answering your question about the relation between the maneuverability and the airplane weight, the relation is just a "simple" physics problem. You just need to know the airplane characteristics like the center of gravity, the different aerodynamic factors and the effect of deflecting the control surfaces. When you solve the six equations with six variables of the differential system you can find how any characteristic of the airplane affects its maneuverability.

Differential equation system of an airplane flight mechanics

Finally, as you say, when the weight is low, the needed lift is less but this does not affect the V-n diagram because n stays more or less constant because: $n=\frac{L}{W}$. This diagram just shows us which are the relation between the aerodynamic forces and the weight. We all know that the weight is one of the problems for an airplane but it also helps to alleviate the bending moment on the wing root, that is why the last fuel tanks that are emptied on an aircraft are the ones that are further away from the fuselage.

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I'll be using the Vn chart for A-10A and F-4J as an example, showing the effect of weight on both subsonic and supersonic planes.

There're two aspects in the V-n chart that takes weight into account:

  1. The lift limit line, at the left boundaries of the chart, representing the stall or flights at critical AOA if such AOA is attainable.
  2. The structural limit, at the upper boundaries of the chart, representing the operational load factor limitations.

V-n ($n_z$) chart of A-10A with 30000 lbs gross weight:

A-10A 30000 lbs V-n

V-n chart of A-10A with 46000 lbs gross weight:

A-10A 46000 lbs V-n

A sea-level V(Mach)-n chart of F-4J with 3 different gross weights:

F-4J V-n

For the lift limit, the maximum available lift at critical AOA is fixed with the same condition, e.g. the same dynamic pressure (affects total lift with the same $C_L$), elevator position (which can be limited by the pilot or flight control system), static margin (which affects the lift generated by the elevator for pitch trimming, and also the pitching moment characteristics for a change in maximum attainable AOA), altitude, mach number (affects $C_L$), etc. So the fixed maximum available lift at stall, combined with an increased weight, results in a reduction of the achievable load factor, by the equations listed below, and that's why the lift limit line moves to the right as weight is increased.

  • $n$ = (lift + thrust * sinα) / weight
  • $n_z$ = normal force / weight = (lift * cosα + drag * sinα) / weight

It's also interesting to note which load factor the V-n chart is using. For example, the A-10A chart is specific that normal load factor is used, but the F-4J chart only says 'acceleration', so you can only guess. But if you assume AOA=0, then they both equals to Lift / Weight.

For the structural limit, things would get pretty complicated, e.g. if you consider bending moment (like some aircraft such as C-5 and F-22, deploys symmetric upward aileron deflection to reduce wing bending by reducing lift at outer wing sections), mach number (as g-limit decreases at transonic and supersonic speeds), asymmetric maneuvers like rolling (with increased pitching moment caused by inertial roll coupling), and non-steady streams (like gust and dynamic pitching maneuver from the contribution of $C_z$q and $C_z$$a$-dot).

But I'll keep it simple and assuming we're subsonic with steady streams, and weight is added only at center of gravity, wing bending is neglected and the wing is perfectly aligned with the body X axis. So the total force that is perpendicular to the wing is the normal force.

  • normal force = $n_z$ * weight

Consider an important quote from one of the flight manuals: The aircraft structure, particularly the wings, can only withstand certain maximum forces acting on it.

So the normal force is fixed if neglecting all the above factors, and a decreased weight would mean a higher $n_z$ limit for the structure. But $n_z$ will also cap at a fixed design limit. So what you'll see is basically a decreased g-limit if weight is increased above a certain threshold:

F-4J g-limit

Coincidentally the maneuvering speed doesn't change in these charts, as the lift limit moves to the right and at the same time, the structural limit moves downwards.

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  • $\begingroup$ Thanks, these are some insightful charts that help illustrate that the physical structural limitations on an aircraft are a function of aerodynamic loads, and therefore the load factor at which structural limits are reached decreases as aircraft weight increases. However, for planes certified under 14 CFR Part 23 as an example, limits are set in terms of load factor, without allowing for for increased load factors at lighter weights, which would still respect the structural limitations of the aircraft. $\endgroup$ Commented Aug 29 at 1:42
  • $\begingroup$ Do you have any resources as to why this is the case? It certainly seems simple, and load factor maps more directly to what a pilot feels during operation, but I'd love to find better references that say why this is the case, especially when it is at the expense of restricting aircraft capabilities at weights less than max. $\endgroup$ Commented Aug 29 at 1:49

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