36
$\begingroup$

Related to this answer: with velocities so different at forward going and rearward going blade, why does the helicopter not roll over? The higher airspeed at the forward going blade should cause more lift, shouldn't it?

From J. Gordon Leishman, Principles of Helicopter Aerodynamics

$\endgroup$
  • 2
    $\begingroup$ Related: Can a helicopter stall? $\endgroup$ – mins Nov 18 '17 at 12:58
  • $\begingroup$ It seems that the answer to this question can be done in three words: flapping and feathering. :) $\endgroup$ – KorvinStarmast Nov 20 '17 at 16:21
36
$\begingroup$

Juan de la Cierva's first autogiro did roll over, twice, and he then applied the principle of blade flapping, a stroke of genius. Flapping is created by allowing the blade to move up and down. Depending on rotor head design this is done in different ways:

  • By a flapping hinge at the hub, allowing vertical rotation.
  • By a teetering hinge on two-blade designs, where both blades together are hinged so they can teeter-totter, one flapping up while the other flaps down.

The lift stays equal at both sides because of blade flapping. If the blades can freely travel up- and downwards, the forward going blade indeed experiences more lift, but as an effect of this starts to travel upwards and reduces its angle of attack. The rearward going blade experiences the reverse, less lift makes the blade descend and increases angle of attack. The lift distribution with and without flapping is depicted in this figure from Prouty, Helicopter Performance, Stability and Control:

enter image description here

The local angle of attack distribution of an example helicopter travelling at 115 kts looks like this:

enter image description here

The rearward going blade has a local AoA of 9°, not very far from stall. Increasing airspeed will at one point result in retreating blade stall, with associated loss of lift and increase of drag, and then the helicopter will start to roll over.

Notice that the reverse flow region is not really a big problem in lift creation:

  • It is close to the disk centre, where lift creation is minimal anyhow.
  • The loss of lift is reduced because of the increased AoA
  • Not only lift reverses, drag is negative as well: in this region the airstream actually helps to propel the blade, reducing the required profile power a bit.
$\endgroup$
  • 1
    $\begingroup$ Sometimes, it's difficult to understand how the flapping cyclically changes the AoA of the blade. This diagram, taken from the 'Rotary Wing Forum' shows the blade profile as seen from the rotorhead axis and as seen from the real, blade tip axis... [![enter image description here][1]][1] [1]: i.stack.imgur.com/hI3E2.png $\endgroup$ – xxavier Nov 18 '17 at 10:14
  • $\begingroup$ I thought the answer to the asymmetric lift issue is not hinges allowing the blades to rise and fall but hinges on the other axis allowing the blades to move back and forth - essentially varying the rate at which they advance or retreat. $\endgroup$ – Anthony X Nov 19 '17 at 2:05
  • 1
    $\begingroup$ @AnthonyX The lead-lag hinges are there to prevent fatigue failure in the blades: as the blade moves up, the rotational inertia changes, kind of like a figure skater spinning faster when pulling in their arms. The blades do speed up and slow down during the rotation as a consequence of going up and down, but it is a secondary, unwanted effect. Mounting a lead-lag hinge prevents once-per-cycle loads on the blade root from happening. $\endgroup$ – Koyovis Nov 19 '17 at 2:19
5
$\begingroup$

You are correct that the advancing blade does create more lift than the retreating blade, and you are correct in that flapping counteracts this asymmetric lift. However, this is a much larger effect which comes into play any time there is asymmetric lift across the main rotor:

Gyroscopic Precession

Gyroscopic precession is the (very counter-intuitive) physics phenomenon wherein torque applied to an object with a lot of angular momentum (from the main rotor in this case) actually causes rotation of that object roughly 90° degrees later in that rotation's direction.

Gyroscopic Precession Diagram

Thus, the increased lift on the advancing blade actually results in a pitch-up action, rather than a roll-left, like you might expect.

This even caught Igor Sikorsky off guard during flight testing of Sikorsky's first helicopter:

The design team was not familiar with the fact that a spinning rotor had gyroscopic properties (precession) which required an input 90 degrees in rotation before it became effective. The VS-300 therefore rolled left when the cyclic stick was pushed forward. The initial pilots, Igor Sikorsky and Serge Gluhareff, had no idea whether the control problems were caused by the helicopter design or pilot technique.

copters.com describes the phenomenon in more detail, and Smarter Every Day has a fantastic video explaining it as well.

$\endgroup$
  • 2
    $\begingroup$ I don't see the need to invoke a gyroscopic effect. The articulated blades are free to move in flapping, and as lift increases at '3 o'clock' (or 9 o'clock; it depends which way the rotor turns...) the blade flaps upwards, reaching the maximum culmination at 12 o'clock. The retreating blade, lacking lift, behaves precisely in the opposite way, thus sinking from 9 o'clock (or 3 o'clock) to reach the maximum depression at 6 o'clock. All that is caused by aerodynamic forces alone... $\endgroup$ – xxavier Nov 18 '17 at 19:00
  • $\begingroup$ Yes what you describe happens when cyclic pitch is applied to the blades. It is the answer to another question though. $\endgroup$ – Koyovis Nov 18 '17 at 22:56

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.