I have been wondering about this for quite a while and can't find an answer.


2 Answers 2


For supersonic speed, putting the wings near the center of gravity would be a good start. Even better, place the wing's center slightly aft of the center of gravity in a conventional configuration.

Lockheed F-104 in flight

Lockheed F-104 in flight (picture source)

If you use rotating wings, placing their roots right above the center of gravity has worked well, too, especially if there is only one attachment point for them.

AS 355 Ecureuil helicopter

AS 355 Ecureuil helicopter (picture source)

If there is more than one attachment point, however, the rotating wings should be at opposite ends of the fuselage, quite a bit away from the center of gravity.

Boeing-Vertol CH-46

Boeing-Vertol CH-46 helicopter (picture source)

At subsonic speed it is advantageous to stretch the wings out sideways, so at least their tips are again quite a bit away from the center of gravity.

Nimeta single-seat glider

Nimeta single-seat glider (picture source)

And then there are some odd designs which try to separate the wings from the center of gravity as much as possible, and they still fly.

Rutan Proteus tandem wing

Rutan Proteus tandem wing (picture source)

So there is no general rule. Maybe these answers help to answer your questions about wing placement relative to the center of gravity.


Absolutely not, CG is a variable.

The wing creates a center of lift (can be refered to depending on what you're trying to achieve as center of pressure or aerodynamic center).

CG works in a partnership with the center of pressure and the horizontal stabilizer to give the aircraft it's stability characteristics.

  • $\begingroup$ Would be good to mention the typical relation between Cg and the wings / weight and balance to give a "full" answer. $\endgroup$ Jan 13, 2017 at 12:44
  • $\begingroup$ @Notts90 agreed, feel free to add to it as I have already passed my ATPL mass and balance exam 3 months ago! $\endgroup$
    – gaveasky
    Jan 13, 2017 at 12:49

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.