Why does the critical angle of attack reduce with increasing mach number or What is the effect of compressibility on critical angle of attack?
1 Answer
First, I have to define what the critical angle of attack is:
When an aerodynamicist speaks of critical conditions, he or she means the condition when the speed of sound is reached locally. The critical Mach number is the speed, measured in multiples of the speed of sound, when the top local speed in a flow field equals the speed of sound.
The critical angle of attack is the one when the local flow speed first reaches the speed of sound. Since it depends on the initial flow speed, it is only valid for a given flight speed.
Two parameters are responsible for the local increase in speed: Thickness and angle of attack. A body needs to displace air, so the air will squeeze around it, speeding up in the process (or slowing down in fully supersonic flow).
When the angle of attack is increased, the stagnation point moves below the airfoil nose so the air flowing over the top of the wing needs to negotiate its leading edge first. This speeds it up and leads to a suction peak. Another view of the same phenomenon is that increasing suction on the upper side of the airfoil will accelerate the air flowing towards it.
With a higher flight speed, less local flow acceleration can be tolerated before the critical conditions are reached. There is even a maximum speed in that suction region of high local curvature that will not be exceeded in subsonic flight and which limits the maximum possible lift coefficient. Higher flight speed leaves less margin, so the angle of attack for maximum lift is reduced with increasing flight speed.
If by critical angle of attack you mean the one where maximum lift is reached (conventionally called stall angle of attack), please read here how it can be influenced. Depending on the flight Mach number, flight speed should be increased or decreased to maximize it.
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1$\begingroup$ I believe that the question was not regarding the angle at which the flow reaches supersonic speed but as the angle at which the maximum $C_L$ starts to decrease. Why the "conventional" critical angle of attack in "$C_L$-$\alpha$" graph starts to decreases with Mach number, and I would like to add the sub-question, why the gradient of the same graph increases with the Mach number? $\endgroup$– DarjanApr 17, 2020 at 22:30
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$\begingroup$ @Darjan So why did the question not ask for it directly? We use standards in terminology for a reason and questions can be edited. Besides, your sub-question deserves its own question here. And why did you feel the need to downvote instead of improving the answer? This is odd. $\endgroup$ Apr 18, 2020 at 5:29
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$\begingroup$ Thank you for the reply, I will post that question later today. I downvoted it because I thought that the answer was not satisfactory. I see that you edited the question with regard to the "conventional" angle of attack, so I will cancel my downvote. $\endgroup$– DarjanApr 18, 2020 at 14:06