I searched for an infamous golf ball question on this site but did not find any, so I guess it's time for one.

Would a dimpled surface like a golf ball somehow improve the aerodynamics of an airplane? (there are many planes for many purposes, so let's just go with my favorite: large commerical passenger planes, Mach 0.85 cruise, several hundred tons loaded weight).

They actually tried this for a car on myth busters and they claimed an 11% improvement in miles-per-gallon, so you can't say the question has no merit. Unfortunately, they did not try it for an airplane.

  • 7
    $\begingroup$ Related: Aerodynamic Analysis of Dimple Effect on Aircraft Wing $\endgroup$
    – mins
    Jan 29, 2016 at 7:23
  • 1
    $\begingroup$ An off topic alternative is a vacuum system to "suck" air from the boundary layer close to the wings. It's been investigated several times even on supersonic aircraft. It has a tendency to clog up the pores, but it may be of interest: en.wikipedia.org/wiki/Boundary_layer_suction $\endgroup$
    – Andy
    Jan 29, 2016 at 8:55
  • 2
    $\begingroup$ At first I thought "What kind of question is this?", but after looking into it, it is a reasonable thing to ask. It looks as though such dimples would have a similar effect to vortex generators, so it follows that dimples might be good in some places but not everywhere. I look forward to seeing an informed answer to this question. $\endgroup$
    – Ben
    Jan 29, 2016 at 11:45
  • $\begingroup$ @Ben I have those same suspicions. Right now my best guesses for dimple locations are the rear half of the wing, or maybe just the underside of the rear half. For lifting bodies, who knows? $\endgroup$
    – DrZ214
    Jan 29, 2016 at 12:05
  • 1
    $\begingroup$ Related: physics.stackexchange.com/questions/109395/… $\endgroup$ Jan 29, 2016 at 12:21

2 Answers 2


Golf ball has dimples on its surface because we want a turbulent boundary layer. Golf ball is a bluff body (i.e. the drag is dominated by pressure drag). Hence, the drag on a sphere is dominated by the separation on the rear face. If we could minimize that, the drag would be reduced.

The following figure shows the variation of drag coeffecient of a sphere with Reynolds number.


Image from wfis.uni.lodz.pl, taken from (Hoerner 1965)

As can be seen, the drag reduces at the critical Reynolds number, which is the point where separation takes place. Because of separation, the wake in the rear of the sphere (or ball) is reduced, which reduces drag. So, if the boundary layer of a sphere can be made turbulent at a lower Reynolds number (by some means), then the drag should also go down at that Reynolds number, as a result of the reduced wake. This can be seen in the following picture, where the flow has been made turbulent using a trip wire.


Flow over a sphere: (a) Reynolds number = 15,000; (b) Reynolds number = 30,000, with trip wire. Image from princeton.edu

That is the purpose of having dimples in a golf ball- to reduce drag by inducing turbulence and delaying separation (this can be achieved by increasing the Reynolds number; but we are limited by the ball speed). The resulting wake is much smaller due to the delayed separation.

In case of a streamlined shape (like aircraft wing), the propotion of pressure drag is small, as can be seen below.

Drag prop

Image from pilotfriend.com

In case of streamlined shapes, the pressure drag is small because the wake is small. The net result is that 'tripping' the boundary layer as in bluff bodies is not a good idea (a laminar flow causes less friction drag than a turbulent one).

The aircrafts do use similiar devices, via the vortex generator, which are used mainly to delay flow separation.

  • $\begingroup$ Just to relentlessly pursue the idea, are you effectively saying that the only place that is possibly viable for dimples is a place where the boundary layer has separated? (such as that small separated wake in the 3rd entry (the airfoil) of the final picture?) $\endgroup$
    – DrZ214
    Jan 29, 2016 at 13:09
  • $\begingroup$ @DrZ214 I'm not sure why you'd want dimples there. The dimples cause flow to become turbulent. The golf balls have dimples all around because you don't know which direction it would fly. $\endgroup$
    – aeroalias
    Jan 29, 2016 at 13:27
  • 1
    $\begingroup$ @DrZ214, no, a bit ahead of that. When the flow has separated, you can't do anything about it any more. But if it is about to separate, making it turbulent will delay the separation. $\endgroup$
    – Jan Hudec
    Jan 29, 2016 at 13:54
  • $\begingroup$ " the drag reduces at the critical Reynolds number, which is the point where separation takes place" should that be "where turbulence takes place"? $\endgroup$
    – Federico
    May 28, 2019 at 5:55

Yes, the question has merit!

Short answer

It depends on the size and speed of the airplane. An airliner is too large and flies too fast to benefit from a dimpled surface. Dimpling the surface would actually increase drag. But some "dimpling" helps at the scale of model aircraft.


It all comes down to the flow condition at the point where flow separation occurs. In calm air, every boundary layer starts as a laminar boundary layer. Since the energy transfer across the stratified flow in the laminar boundary layer is reduced to shear, the molecules close to the wall will lose speed quickly, so that even at a modest pressure rise downstream separation occurs quickly.

Inside the laminar boundary layer, small disturbances become less and less damped the higher the local Reynolds number becomes, and at a Reynolds number of around 400,000 in unaccelerated flow some frequencies become unstable (see Tollmien-Schlichting waves) and will eventually create so much cross movement that the boundary layer becomes turbulent. Now parcels of air which flow at high speed in the outer part of the boundary layer will move close to the wall and kick the slow parcels there ahead, greatly reducing the deceleration of the flow close to the wall, at the price of slowing down and expanding the whole boundary layer.

Such a turbulent boundary layer is much better in following a contour with an adverse pressure gradient since it shows less deceleration of the flow at the wall. A pressure rise is generally caused by a contracting body shape. Separation is delayed and the separation, once it occurs, is much smaller. The pressure in separated flow is lower than ambient, so rearward-facing areas with separated flow cause massive drag. Therefore, separation needs to be suppressed as long as possible to minimize drag.

If the contour of a body contracts at a local Reynolds number below that where natural transition to a turbulent boundary layer occurs, the still laminar boundary layer will cause early separation. The dimples of a golf ball help to trip the boundary layer early into its turbulent version, thus delaying separation and reducing drag.

If the local Reynolds number (which is proportional to the product of speed and body length) is higher, such that the boundary layer turns turbulent before the part of the body with the adverse pressure gradient is reached, dimpling the surface will still cause earlier transition, but will not change the separation location. Even worse, it will reduce the area of laminar flow, and the increased area with a turbulent boundary layer will cause more friction drag. The pressure fluctuations along a dimpled surface will weaken the boundary layer, and the dimpled airplane will show earlier and more separation compared to a smooth version.

Dimpling the whole surface is not necessary if the local direction of flow is known. A golf ball needs to have dimples all around so that at least some end up where they can help to trip the boundary layer, but on a wing only a small strip needs such a tripping device, called a turbulator. Some model aircraft and gliders already use them to achieve less separation, but here small dimples are less effective than a zig-zag tape. How it works merits a question of its own.

Spool of zig-zag tape

Spool of zig-zag tape (picture source)


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.