2
$\begingroup$

As an airplane climbs, the best angle of climb airspeed (Vx) increases and the best rate of climb airspeed (Vy) decreases. I can't figure it out, why does it happen? I Hope someone explains it to me I appreciate

$\endgroup$
4
  • 1
    $\begingroup$ Appears to be answered here aviation.stackexchange.com/a/34683/34686 $\endgroup$ Oct 30, 2023 at 19:52
  • $\begingroup$ That answer isn't fully baked. At a minimum, Vx is always slower than Vy. The figure clearly shows them crossing. $\endgroup$ Oct 30, 2023 at 21:38
  • $\begingroup$ @RobMcDonald -- I don't think the linked answer is in error. Note that the vertical axis is not altitude. But yeah I can agree that it doesn't appear to answer the present question. $\endgroup$ Oct 31, 2023 at 12:20
  • $\begingroup$ @quietflyer Good catch. $\endgroup$ Oct 31, 2023 at 16:56

2 Answers 2

2
$\begingroup$

Vx is all about using higher angle of attack (slower airspeed) and excess thrust to climb. The more excess thrust one has, the steeper the angle one can climb.

As altitude increases, thrust output decreases. This is why the plane must lower its angle of climb, reduce its angle of attack, and go faster in order to continue climbing.

Vy is all about using a lower angle of attack and greater airspeed to climb. As thrust output decreases, the aircraft must increase its AoA and lower its airspeed to continue climbing.

At the absolute ceiling altitude, only the most efficient combination of (diminished) thrust, airspeed, and angle of attack will allow level flight. This is where Vx and Vy converge.

$\endgroup$
0
$\begingroup$

The details of this depend on the details of your propulsion model for your aircraft. I.e. how do maximum throttle thrust/power change with airspeed and altitude.

You also need to pay close attention to equivalent vs true airspeed.

$V_y$ is always greater or equal than $V_x$. However, at absolute ceiling, they are equal (and the climb angle and rate of climb are both zero).

So, to start apart and end up together, they either have to increase/decrease, both increase (but at different rates), or both decrease (but at different rates).

For a jet aircraft, we usually approximate the thrust available as constant with airspeed. In this case, Vx will occur at the speed for best L/D, which will be a fixed Ve. In order for Vy to start off greater, but to eventually equal Vx, Vy must decrease with altitude (in terms of Ve).

For a propeller aircraft, we usually approximate the power available as constant with airspeed. In this case, Vy will occur at the speed for minimum power required, which is the speed for best $C_L^{3/2}/C_D$. Which occurs at a fixed lift coefficient and therefore also occurs at a constant $V_e$ with altitude. So, in order for Vx to start off less than, but to eventually equal Vy, Vx must increase with altitude (in terms of Ve).

In reality, neither of these approximations is perfect, so the truth generally lies somewhere in-between. However, working it out to great precision requires very detailed models of the propulsion system.

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .