I came across this helicopter and am wondering what the oblong things on either side of the helicopter are, parallel to the front-back axis, offset from the main body.
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$\begingroup$ Can you post a better photo? Maybe some zoom & other image enhancements? $\endgroup$– curious_catCommented Nov 30, 2015 at 11:30
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$\begingroup$ @curious_cat How's that? $\endgroup$– andrewmh20Commented Nov 30, 2015 at 11:38
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$\begingroup$ Much better, thanks! $\endgroup$– curious_catCommented Nov 30, 2015 at 11:41
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$\begingroup$ @andrewmh20 Can you tell when and where u came across that heli? $\endgroup$– aeroaliasCommented Nov 30, 2015 at 12:32
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$\begingroup$ @aeroalias Israeli skies, and I see from the link below that Israel had some CH-53D's. $\endgroup$– andrewmh20Commented Nov 30, 2015 at 12:35
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2 Answers
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The helicopter is a S-65C-3 Yas'ur (Albatross). It is a CH-53D version similar to USAF HH-53C Pave Low. Here is a photo of the same.
The identification is based on the following:
Six bladed main rotor
The sponsons which hold the fuel
The only variant of CH-53D with in-flight refueling probe in service is the Israeli version. All others (HH-53 and MH-53) have been retired. CH-53E has refueling probe, but it has 7 blades.
Israel ordered 36 of these,of which around 23 are still in service.
answered Nov 30, 2015 at 12:18
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The helicopter is a Sikorsky CH-53 (probably an 'E' model). According to this site, the two sponsons holding the fuel tanks are also the place where the landing gear retract.
EDIT: Probably not an 'E' model as the 'E' model has a seven-blade rotor, while the one in this picture doesn't. I'd say this is a 'D' model or an MH-53 'J' model.
answered Nov 30, 2015 at 11:40
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$\begingroup$ the drawing from wikipedia matches the shape quite well: upload.wikimedia.org/wikipedia/commons/thumb/c/cf/… $\endgroup$– FedericoCommented Nov 30, 2015 at 11:43
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$\begingroup$ @Federico, edited, because of model mismatch... $\endgroup$ Commented Nov 30, 2015 at 11:55
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$\begingroup$ @MarcoSanfilippo CH-53D makes sense with location --see comment on question. $\endgroup$ Commented Nov 30, 2015 at 12:36
